Optimal. Leaf size=69 \[ -\frac{\left (a^3+b^3\right ) \coth (c+d x)}{d}+a^3 x-\frac{(a+b)^3 \coth ^5(c+d x)}{5 d}-\frac{(a-2 b) (a+b)^2 \coth ^3(c+d x)}{3 d} \]
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Rubi [A] time = 0.109348, antiderivative size = 69, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.13, Rules used = {4141, 1802, 207} \[ -\frac{\left (a^3+b^3\right ) \coth (c+d x)}{d}+a^3 x-\frac{(a+b)^3 \coth ^5(c+d x)}{5 d}-\frac{(a-2 b) (a+b)^2 \coth ^3(c+d x)}{3 d} \]
Antiderivative was successfully verified.
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Rule 4141
Rule 1802
Rule 207
Rubi steps
\begin{align*} \int \coth ^6(c+d x) \left (a+b \text{sech}^2(c+d x)\right )^3 \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \left (1-x^2\right )\right )^3}{x^6 \left (1-x^2\right )} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \left (\frac{(a+b)^3}{x^6}+\frac{(a-2 b) (a+b)^2}{x^4}+\frac{a^3+b^3}{x^2}-\frac{a^3}{-1+x^2}\right ) \, dx,x,\tanh (c+d x)\right )}{d}\\ &=-\frac{\left (a^3+b^3\right ) \coth (c+d x)}{d}-\frac{(a-2 b) (a+b)^2 \coth ^3(c+d x)}{3 d}-\frac{(a+b)^3 \coth ^5(c+d x)}{5 d}-\frac{a^3 \operatorname{Subst}\left (\int \frac{1}{-1+x^2} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=a^3 x-\frac{\left (a^3+b^3\right ) \coth (c+d x)}{d}-\frac{(a-2 b) (a+b)^2 \coth ^3(c+d x)}{3 d}-\frac{(a+b)^3 \coth ^5(c+d x)}{5 d}\\ \end{align*}
Mathematica [B] time = 1.0977, size = 303, normalized size = 4.39 \[ \frac{\text{csch}(c) \text{csch}^5(c+d x) \left (-90 a^2 b \sinh (4 c+3 d x)+18 a^2 b \sinh (4 c+5 d x)+180 a^2 b \sinh (d x)+180 a^3 \sinh (2 c+d x)-140 a^3 \sinh (2 c+3 d x)-90 a^3 \sinh (4 c+3 d x)+46 a^3 \sinh (4 c+5 d x)+150 a^3 d x \cosh (2 c+d x)+75 a^3 d x \cosh (2 c+3 d x)-75 a^3 d x \cosh (4 c+3 d x)-15 a^3 d x \cosh (4 c+5 d x)+15 a^3 d x \cosh (6 c+5 d x)+280 a^3 \sinh (d x)-150 a^3 d x \cosh (d x)-180 a b^2 \sinh (2 c+d x)+60 a b^2 \sinh (2 c+3 d x)-12 a b^2 \sinh (4 c+5 d x)+60 a b^2 \sinh (d x)-80 b^3 \sinh (2 c+3 d x)+16 b^3 \sinh (4 c+5 d x)+160 b^3 \sinh (d x)\right )}{480 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.046, size = 199, normalized size = 2.9 \begin{align*}{\frac{1}{d} \left ({a}^{3} \left ( dx+c-{\rm coth} \left (dx+c\right )-{\frac{ \left ({\rm coth} \left (dx+c\right ) \right ) ^{3}}{3}}-{\frac{ \left ({\rm coth} \left (dx+c\right ) \right ) ^{5}}{5}} \right ) +3\,{a}^{2}b \left ( -1/2\,{\frac{ \left ( \cosh \left ( dx+c \right ) \right ) ^{3}}{ \left ( \sinh \left ( dx+c \right ) \right ) ^{5}}}+3/8\,{\frac{\cosh \left ( dx+c \right ) }{ \left ( \sinh \left ( dx+c \right ) \right ) ^{5}}}+3/8\, \left ( -{\frac{8}{15}}-1/5\, \left ({\rm csch} \left (dx+c\right ) \right ) ^{4}+{\frac{4\, \left ({\rm csch} \left (dx+c\right ) \right ) ^{2}}{15}} \right ){\rm coth} \left (dx+c\right ) \right ) +3\,a{b}^{2} \left ( -1/4\,{\frac{\cosh \left ( dx+c \right ) }{ \left ( \sinh \left ( dx+c \right ) \right ) ^{5}}}-1/4\, \left ( -{\frac{8}{15}}-1/5\, \left ({\rm csch} \left (dx+c\right ) \right ) ^{4}+{\frac{4\, \left ({\rm csch} \left (dx+c\right ) \right ) ^{2}}{15}} \right ){\rm coth} \left (dx+c\right ) \right ) +{b}^{3} \left ( -{\frac{8}{15}}-{\frac{ \left ({\rm csch} \left (dx+c\right ) \right ) ^{4}}{5}}+{\frac{4\, \left ({\rm csch} \left (dx+c\right ) \right ) ^{2}}{15}} \right ){\rm coth} \left (dx+c\right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.25417, size = 1115, normalized size = 16.16 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.37112, size = 1249, normalized size = 18.1 \begin{align*} -\frac{{\left (23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right )^{5} + 5 \,{\left (23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right ) \sinh \left (d x + c\right )^{4} -{\left (15 \, a^{3} d x + 23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \sinh \left (d x + c\right )^{5} - 5 \,{\left (5 \, a^{3} - 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right )^{3} + 5 \,{\left (15 \, a^{3} d x + 23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3} - 2 \,{\left (15 \, a^{3} d x + 23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right )^{2}\right )} \sinh \left (d x + c\right )^{3} + 5 \,{\left (2 \,{\left (23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right )^{3} - 3 \,{\left (5 \, a^{3} - 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right )\right )} \sinh \left (d x + c\right )^{2} + 10 \,{\left (5 \, a^{3} + 9 \, a^{2} b + 12 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right ) - 5 \,{\left (30 \, a^{3} d x +{\left (15 \, a^{3} d x + 23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right )^{4} + 46 \, a^{3} + 18 \, a^{2} b - 12 \, a b^{2} + 16 \, b^{3} - 3 \,{\left (15 \, a^{3} d x + 23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )} \cosh \left (d x + c\right )^{2}\right )} \sinh \left (d x + c\right )}{15 \,{\left (d \sinh \left (d x + c\right )^{5} + 5 \,{\left (2 \, d \cosh \left (d x + c\right )^{2} - d\right )} \sinh \left (d x + c\right )^{3} + 5 \,{\left (d \cosh \left (d x + c\right )^{4} - 3 \, d \cosh \left (d x + c\right )^{2} + 2 \, d\right )} \sinh \left (d x + c\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.60703, size = 284, normalized size = 4.12 \begin{align*} \frac{15 \, a^{3} d x - \frac{2 \,{\left (45 \, a^{3} e^{\left (8 \, d x + 8 \, c\right )} + 45 \, a^{2} b e^{\left (8 \, d x + 8 \, c\right )} - 90 \, a^{3} e^{\left (6 \, d x + 6 \, c\right )} + 90 \, a b^{2} e^{\left (6 \, d x + 6 \, c\right )} + 140 \, a^{3} e^{\left (4 \, d x + 4 \, c\right )} + 90 \, a^{2} b e^{\left (4 \, d x + 4 \, c\right )} + 30 \, a b^{2} e^{\left (4 \, d x + 4 \, c\right )} + 80 \, b^{3} e^{\left (4 \, d x + 4 \, c\right )} - 70 \, a^{3} e^{\left (2 \, d x + 2 \, c\right )} + 30 \, a b^{2} e^{\left (2 \, d x + 2 \, c\right )} - 40 \, b^{3} e^{\left (2 \, d x + 2 \, c\right )} + 23 \, a^{3} + 9 \, a^{2} b - 6 \, a b^{2} + 8 \, b^{3}\right )}}{{\left (e^{\left (2 \, d x + 2 \, c\right )} - 1\right )}^{5}}}{15 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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